8.2 Collision Theory and Surface Area
GCSE Chemistry · AQA · Chapter 8: Rates and Equilibrium
A free GCSE Chemistry lesson for AQA (8462) from OBA School: why particles must collide with enough energy to react, what activation energy is, and why smaller pieces react faster. Watch the video, read the explanation and worked examples, then try the revision questions. You can work through the full lesson, with every video, practice quizzes and printable worksheets with mark schemes, in our free online course.
What you will learn
- State collision theory and define activation energy
- Draw and label a reaction profile showing the activation energy
- Calculate surface area to volume ratios for cubes, including nanoparticles in standard form
- Explain, using collision theory, why increasing surface area increases the rate of reaction
- Interpret graphs comparing powders and lumps
Key words
- Collision theory: Chemical reactions can only happen when reacting particles collide with sufficient energy.
- Activation energy: The minimum amount of energy that particles must have to react when they collide.
- Successful collision: A collision with energy equal to or greater than the activation energy, so a reaction happens.
- Frequency of collisions: How many collisions happen each second.
- Surface area to volume ratio: Surface area ÷ volume. Cutting a solid into smaller pieces increases it.
- Reaction profile: A diagram showing the energy of reactants and products and the activation energy.
Collision theory
Particles in liquids, gases and solutions are always moving. For a reaction to happen, reacting particles must collide, and the collision must have at least the activation energy. Most collisions do not have enough energy: the particles just bounce apart.
Key fact: The rate of reaction depends on the frequency of successful collisions: more successful collisions per second means a faster reaction. So anything that makes collisions more frequent, or gives a greater proportion of them enough energy, speeds up the reaction.
Activation energy and reaction profiles
A reaction profile shows energy on the vertical axis. The activation energy is the difference between the energy of the reactants and the top of the “hill”. Think of it as an energy barrier that the colliding particles must get over.
Exam tip: Measure activation energy from the reactants line to the peak, not from zero and not from the products.
What affects the rate?
- Surface area of a solid; What changes smaller pieces / powder; Effect on collisions more frequent collisions (this lesson)
- Temperature; What changes higher temperature; Effect on collisions more frequent and more energetic collisions (8.3)
- Concentration or pressure; What changes more particles in the same volume; Effect on collisions more frequent collisions (8.4)
- Catalyst; What changes added catalyst; Effect on collisions lower activation energy, so more collisions are successful (8.5)
Surface area and surface area to volume ratio
A solid can only react at its surface, where particles of the other reactant can reach it. If you break a solid into smaller pieces, more of its particles are on the surface. The total surface area goes up, even though the mass stays the same.
Worked example: surface area to volume ratio
A cube has sides of 3 cm. Each face = 3 × 3 = 9 cm², and a cube has 6 faces.
Surface area = 6 × 9 = 54 cm². Volume = 3 × 3 × 3 = 27 cm³. SA : V = 54 : 27 = 2 : 1.
Cut into 1 cm cubes: 27 cubes, each with SA = 6 cm². Total SA = 27 × 6 = 162 cm². SA : V = 162 : 27 = 6 : 1.
Answer: the ratio increases from 2 : 1 to 6 : 1
Maths skill: For any cube, SA : V = 6 ÷ side length. So if the side is made 10 times smaller, the surface area to volume ratio becomes 10 times bigger. Always state the unit of length: a ratio of 6 per cm is not the same as 6 per m.
Worked example: surface area to volume ratio of a nanoparticle (standard form)
A cube-shaped nanoparticle has sides of 20 nm. 1 nm = 1 × 10⁻⁹ m, so the side = 2 × 10⁻⁸ m.
SA = 6 × (2 × 10⁻⁸)² = 6 × 4 × 10⁻¹⁶ = 2.4 × 10⁻¹⁵ m². V = (2 × 10⁻⁸)³ = 8 × 10⁻²⁴ m³.
SA : V = (2.4 × 10⁻¹⁵) ÷ (8 × 10⁻²⁴) = 3 × 10⁸ per m. (Check: 6 ÷ (2 × 10⁻⁸) = 3 × 10⁸.)
A 2 cm sugar cube (side 0.02 m) has SA : V = 6 ÷ 0.02 = 300 per m: a million times smaller.
Answer: 3 × 10⁸ per metre – this is why nanoparticles can be so reactive
Explaining the effect of surface area
Smaller pieces → larger surface area to volume ratio → more particles exposed → more frequent collisions → faster rate.
The energy of the collisions does not change, so the proportion of collisions that are successful stays the same. There are simply more collisions each second.
Here 0.20 g of calcium carbonate reacted with excess hydrochloric acid, once as powder and once as large chips.
The final volume is the same because the same mass of calcium carbonate (the limiting reactant) was used. Surface area changes how fast the gas is made, not how much.
Key fact: Fine powders, such as flour, custard powder or coal dust, have such a huge surface area that a cloud of them in air can ignite and explode. Factories control dust for this reason.
Common mistakes
- Saying “the particles collide more”. Say more frequent collisions (more collisions per second).
- Saying a bigger surface area gives the particles more energy. Surface area only changes the frequency of collisions.
- Saying powder makes more product. With the same mass of solid, the final amount of product is the same.
- Thinking every collision causes a reaction. Only collisions with energy at least equal to the activation energy are successful.
- Measuring activation energy from the products or from zero on a reaction profile.
Revision questions
Try these, then check your answers below each one.
Question 1. What is the activation energy of a reaction? (Choose from: The energy given out by the reaction, The minimum energy that particles must have to react when they collide, The energy of the products, The average energy of the particles.)
Answer: The minimum energy that particles must have to react when they collide
Working: Activation energy is the minimum energy colliding particles need for a reaction to happen.
Question 2. A collision between particles that has enough energy to cause a reaction is called a ______ collision. Fill in the missing word.
Answer: successful
Working: A successful collision has energy equal to or greater than the activation energy.
Question 3. A cube of calcium carbonate has sides of 4 cm. Calculate its surface area to volume ratio, written as a number : 1. Give just the number.
Answer: 1.5
Working: SA = 6 × 4 × 4 = 96 cm². V = 4 × 4 × 4 = 64 cm³. 96 ÷ 64 = 1.5, so SA : V = 1.5 : 1.
Related lessons
- Previous lesson: 8.1 Rate of Reaction
- Next lesson: 8.3 The Effect of Temperature
- In this chapter: 8.4–8.5 The Effect of Concentration, Pressure and Catalysts
- In this chapter: 8.6–8.7 Reversible Reactions and Energy Changes
- In this chapter: 8.8–8.9 Dynamic Equilibrium and Altering Conditions
Continue in the full course
This lesson is section 8.2 (AGCCH0802) of our free GCSE Chemistry course for AQA. In the full course you get every video for this section, a self-marking practice quiz, a printable worksheet with a mark scheme, chapter tests, and your progress saved. Go to the full GCSE Chemistry course.